Decimal Number to hexadecimal number in C

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Steps to convert Decimal number into Hexadecimal number - 

1. Divide the decimal number by 16. Treat the division as an integer division.
2. Write down the remainder (in hexadecimal, ie. if the remainder is 12, write down "C").
3. Divide the result again by 16. Treat the division as an integer division.
4. Repeat step 2 and 3 until result is less than 1.
5. The hexadecimal value is the digit sequence of the remainders from the last to first. (So if you had 001, it's 100.)

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Sample Output - 

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Code - 

/* Program to convert Decimal number into Hexadecimal number */

#include<stdio.h>

#include<conio.h>

int main()
{
int decimal_number = 0, temp_number = 0, remainder = 0, counter = 0, i  = 0, value = 0;

char hexadecimal_number[10];

printf("\n\t __ Program to convert Decimal number into Hexadecimal number __");

printf("\n\n\n  Enter the Decimal Number - ");

scanf("%d",&decimal_number);

temp_number = decimal_number;

while(temp_number > 1)
{
remainder = temp_number % 16;

temp_number = temp_number / 16;

value = 0;

if (remainder >= 0 && remainder <= 9)
{
value = 48;

for ( i = 1; i <= remainder; i ++)
{
value = value + 1;
}
}
else if (remainder >= 10 && remainder <= 15)
{
value = 65;

for ( i = 11; i <= remainder; i ++)
{
value = value + 1;
}
}

hexadecimal_number[counter] = (char)value;

counter++;
}

printf("\n\n  Hexadecimal Conversion of %d (base 10) is ", decimal_number);

for( i =  counter - 1 ; i >= 0; i -- )
{
printf("%c", hexadecimal_number[i]);
}

printf(" (base 16)");

getch();

return 0;
}